Question

In a rectangle ABCD, AB = 7 cm and AD = 25 cm. Find the height of a triangle whose base is AB and whose area is two times the area of the rectangle ABCD.

Answer 1

Area of rectangle ABCD = AB x AD = 7 x 25 = 175cm²

Area of triangle whose base is AB = `(1)/(2) xx "AB" xx "Height" = (1)/(2) xx 7 xx "Height"`

Now,
Area of triangle whose base is AB = 2 x Area of rectangle ABCD

⇒ `(1)/(2) xx 7 xx "Height"` = 175

⇒ Height 

= `(175 xx 2)/(7)`
= 50cm.