Question

In a reaction \[\ce{x + y + z2 -> xyz2}\] identify the Limiting reagent if any, in the following reaction mixture.

200 atoms of x + 200 atoms of y + 50 molecules of z₂

Answer 1

Reaction: \[\ce{x + y + z2 -> xyz2}\]

200 atoms of x + 200 atoms of y + 50 molecules of z₂.

According to the reaction, 1 atom of x reacts with one atom of y and one molecule of z to give the product.

In case 200 atoms of x, 200 atoms of y react with 50 molecules of z₂ (4 part) i.e. 50 molecules of z₂ react with 50 atoms of x and 50 atoms of y.

Hence z is the limiting reagent.