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प्रश्न
In a reaction, \[\ce{A + B2 -> AB2}\]
Identify the limiting reagent, if any, in the following reaction mixture.
2 mol A + 3 mol B
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उत्तर
\[\ce{A + B2 -> AB2}\]
This is a balanced chemical equation showing that 1 mole of A reacts with 1 mole of B₂ to form 1 mole of AB₂.
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A = 2 moles
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B = 3 moles
B₂ is diatomic, meaning 1 mole of B₂ contains 2 atoms of B.
So, to find moles of B₂ from 3 moles of B atoms:
Moles of `B_2 = 3/2 = 1.5` mol
A : B2 = 1 : 1
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B₂ (made from B atoms) is less than required to use up all the A.
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So, B₂ is the limiting reagent, i.e., it will run out first and stop the reaction.
Limiting reagent is B
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Identify the limiting reagent, if any, in the following reaction mixture.
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Identify the limiting reagent, if any, in the following reaction mixture.
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Identify the limiting reagent, if any, in the following reaction mixture.
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Identify the limiting reagent, if any, in the following reaction mixture.
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\[\ce{CaCO3(s) + 2HCl (aq) -> CaCl2 (aq) + CO2(g) + H2O (l)}\]
What mass of \[\ce{CaCl2}\] will be formed when 250 mL of 0.76 M \[\ce{HCl}\] reacts with 1000 g of \[\ce{CaCO3}\]? Name the limiting reagent. Calculate the number of moles of \[\ce{CaCl2}\] formed in the reaction.
