हिंदी

In a pentagon ABCDE, show that bar"AB" + bar"AE" + bar"BC" + bar"DC" + bar"ED" = 2bar"AC" - Mathematics and Statistics

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प्रश्न

In a pentagon ABCDE, show that `bar"AB" + bar"AE" + bar"BC" + bar"DC" + bar"ED" = 2bar"AC"`

योग
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उत्तर

LHS = `bar"AB" + bar"AE" + bar"BC" + bar"DC" + bar"ED"`

`= (bar"AB" + bar"BC") + (bar"AE" + bar"ED" + bar"DC")`

`= bar"AC" + bar"AC"`

`= 2bar"AC"` = RHS

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अध्याय 5: Vectors - Miscellaneous exercise 5 [पृष्ठ १९०]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 5 Vectors
Miscellaneous exercise 5 | Q II. 3) | पृष्ठ १९०
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