Question

In a G.P. 729, 243, 81, … find t₇

Answer 1

G.P = 729, 243, 81, ….

t₇ = ?

t_n = arⁿ⁻¹, here a = 729, r = `("t"_2)/("t"_1)`

r = `243/729 = 1/3`

∴ t₇ = `729(1/3)^(7-1) = 729 xx (1/3)^6`

= `729 xx 1/729`

= 1