Advertisements
Advertisements
प्रश्न
If X is a random variable such that P(X = −2) = P(X = −1) = P(X = 2) = P(X = 1) = `1/6` and P(X = 0) = `1/3`, then the mean of X is ______.
विकल्प
`5/3`
1
0
`3/5`
MCQ
रिक्त स्थान भरें
Advertisements
उत्तर
If X is a random variable such that P(X = −2) = P(X = −1) = P(X = 2) = P(X = 1) = `1/6` and P(X = 0) = `1/3`, then the mean of X is 0.
Explanation:
P(X = −2) = P(X = −1)
= P(X = 2) = P(X = 1) = `1/6`
& P(X = 0) = `1/3`
Mean = (−2).P(X = −2) + (−1) P(X = −1) + 0.
P(X = 0) + 1.P(X = 1) + 2Pp(X = 2)
= `-2 xx 1/6 - 1/6 = 0 + 1/6 + 2 xx 1/6`
= Mean = 0
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
