Question

If x is 30% more than y; find : `"y"/("y" - "x")`

Answer 1

Let y = a

Then x = `"a" xx (100 + 30)/100`

`= "a" xx 130/100 = 13/10 "a"`

Now, `"y"/("y" - "x")`

` = "a"/("a" - 13/10"a") = "a"/(-3/10 "a")`

`= ("a" xx 10)/(- 3"a") = - 10/3`