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प्रश्न
If x = `(5ab)/(a − b), a ≠ b,`
- Find: `x/a`
- Using properties of proportion, find: `(x + a)/(x - a)`
योग
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उत्तर
(a) Given: x = `(5ab)/(a − b)`
Multiplying `1/a` on both sides of the equation:
⇒ `x/a = 1/a((5ab)/(a - b))`
⇒ `x/a = (5b)/(a - b)`
(b) Since,
⇒ `x/a = (5b)/(a - b)`
Applying componendo and dividendo, we get:
⇒ `(x + a)/(x - a) = (5b + (a - b))/(5b - (a - b))`
⇒ `(x + a)/(x - a) = (5b + a - b)/(5b - a + b)`
⇒ `(x + a)/(x - a) = (a + 4b)/(6b - a)`
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