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प्रश्न
If x = 3 and y = − 1, find the values of the following using in identify:
\[\left( \frac{3}{x} - \frac{x}{3} \right) \left( \frac{x^2}{9} + \frac{9}{x^2} + 1 \right)\]
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उत्तर
In the given problem, we have to find the value of equation using identity
Given \[\left( \frac{3}{x} - \frac{x}{3} \right) \left( \frac{x^2}{9} + \frac{9}{x^2} + 1 \right)\]
We shall use the identity `(a-b)(a^2 + ab + b^2) = a^3 - b^3`
We can rearrange the \[\left( \frac{3}{x} - \frac{x}{3} \right) \left( \frac{x^2}{9} + \frac{9}{x^2} + 1 \right)\]as
`= (3/x - x/3) ((3/x)^2 + (x/3)^2 + (3/x)(x/3))`
` = (3/x)^3 - (x/3)^3`
\[= \left( \frac{3}{x} \right) \times \left( \frac{3}{x} \right) \times \left( \frac{3}{x} \right) - \left( \frac{x}{3} \right) \times \left( \frac{x}{3} \right) \times \left( \frac{x}{3} \right)\]
\[ = \frac{27}{x^3} - \frac{x^3}{27}\]
Now substituting the value x=3, in `27/x^3 - x^3/27`we get,
`27/3^3 - 3^3/27`
`27/27 - 27/27`
` = 0`
Hence the Product value of \[\left( \frac{3}{x} - \frac{x}{3} \right) \left( \frac{x^2}{9} + \frac{9}{x^2} + 1 \right)\] is `0`.
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