हिंदी

If x = 3 + √2/3 − √2, y = 3 − √2/3 + √2, find xy. - Mathematics

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प्रश्न

If `x = (3 + sqrt(2))/(3 - sqrt(2)), y = (3 - sqrt(2))/(3 + sqrt(2))`, find xy.

योग
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उत्तर

Given: `x = (3 + sqrt(2))/(3 - sqrt(2)), y = (3 - sqrt(2))/(3 + sqrt(2))`

Stepwise calculation:

1. Multiply x and y: 

`xy = ((3 + sqrt(2))/(3 - sqrt(2))) xx ((3 - sqrt(2))/(3 + sqrt(2)))`

2. Since the numerator of x is the denominator of y and vice versa, the terms cancel out: 

`xy = ((3 + sqrt(2))(3 - sqrt(2)))/((3 - sqrt(2))(3 + sqrt(2))`

xy = 1

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अध्याय 1: Rational and Irrational Numbers - Exercise 1E [पृष्ठ ३२]

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नूतन Mathematics [English] Class 9 ICSE
अध्याय 1 Rational and Irrational Numbers
Exercise 1E | Q 8. (iii) | पृष्ठ ३२
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