हिंदी

If the point (\mathrm{P}(6, -3)) lies on the line segment joining points (\mathrm{A}(4, 2)) and (\mathrm{B}(8, 4)) then:

Advertisements
Advertisements

प्रश्न

If the point \(\mathrm{P}(6, -3)\) lies on the line segment joining points \(\mathrm{A}(4, 2)\) and \(\mathrm{B}(8, 4)\) then:

विकल्प

  • \(\mathrm{AP}=\frac{1}{3} \mathrm{AB}\)

  • \(\mathrm{AP}=\frac{1}{4} \mathrm{AB}\)

  • \(\mathrm{PB}=\frac{1}{3} \mathrm{AB}\)

  • \(\mathrm{AP}=\frac{1}{2} \mathrm{AB}\)

MCQ
Advertisements

उत्तर

`bb(AP = 1/2 AB)`

Explanation:

The x-coordinate of P gives the fraction \(\frac{AP}{AB} = \frac{6 - 4}{8 - 4} = \frac{1}{2}\) and the y-coordinate confirms it: \(2 + \frac{1}{2}(4 - 2) = 3\). Hence P is the mid-point and \(AP = \frac{1}{2}AB\).

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 13: Section and Mid-point Formulae - COMPETENCY-FOCUSED QUESTIONS [पृष्ठ २१२]

APPEARS IN

आर.एस. अग्रवाल Mathematics [English] Class 10 ICSE
अध्याय 13 Section and Mid-point Formulae
COMPETENCY-FOCUSED QUESTIONS | Q 12. | पृष्ठ २१२
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×