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If the energy of a ball falling from a height of 10 metres is reduced by 40%, how high will it rebound?

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प्रश्न

If the energy of a ball falling from a height of 10 metres is reduced by 40%, how high will it rebound?

योग
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उत्तर

Given:

Height (h1) = 10 m

PE2 = PE1 - PE1 of 40%

Find: Height (h2)

Formula: P.E. = mgh

Calculations:

PE1 = mgh1   ...(i)

PE2 =  mgh2  ...(ii)

PE2 = PE1 of 60%

Dividing equation (ii) by (i).

`"PE"_2/"PE"_1 = ("mgh"_2)/("mgh"_1)`

`(60%"PE"_1)/("PE"_1) = "h"_2/10`

`60/100 = "h"_2/10`

`"h"_2 = (60 xx 10)/100`

h2 = 6 m

∴ The ball will bounce up to a height of 6 m when it hits the ground.

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अध्याय 2: Work and Energy - Exercises [पृष्ठ २९]

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बालभारती Science and Technology [English] Standard 9 Maharashtra State
अध्याय 2 Work and Energy
Exercises | Q 5. c. | पृष्ठ २९

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