Question

If the coordinates of one end of a diameter of a circle is (3, 4) and the coordinates of its centre is (−3, 2), then the coordinate of the other end of the diameter is

विकल्प

• (0, −3)

• (0, 9)

• (3, 0)

• (−9, 0)

Answer 1

(−9, 0)

Explanation;

Hint:

Let the other end of the diameter be (a, b)

Mid-point of a line =

`((x_1 + x_2)/2, (y_1 + y_2)/2)`

(−3, 2) = `(3 + "a")/2, (4 + "b")/2`

`(3 + "a")/2` = −3

3 + a = −6

a = −6 – 3 = −9

and

`(4 + "b")/2` = 2

4 + b = 4

b = 4 – 4 = 0

The other end is (−9, 0)