Advertisements
Advertisements
प्रश्न
If the complement of an angle is 62°, then find its supplement.
Advertisements
उत्तर
Let the angle be x.
∴ Its complement = 90° – x
According to the question,
90° – x = 62°
⇒ 90° – 62° = x
⇒ x = 28°
∴ Supplement of x = 180° – 28° = 152°
APPEARS IN
संबंधित प्रश्न
Find the supplement of the following angle:

If ∠A and ∠B are supplementary angles and m∠B = (x + 20)°, then what would be m∠A?
Find the measure of the supplements of the following angle.
(90 − x)°
What will be the measure of the supplement of the following angles?
100º
(a + 30)° and (2a)° are the measures of two supplementary angles. What is the measure of each angle?
The angles x – 10° and 190° – x are ______.
If two supplementary angles are in the ratio 1 : 2, then the bigger angle is ______.
Two angles forming a ______ pair are supplementary.
The supplement of an acute is always ______ angle.
