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प्रश्न
If `tan θ + 1/tan θ = 2`, find the value of `tan^2 θ + 1/(tan^2 θ)`.
योग
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उत्तर
Given:
`tan θ + 1/tan θ = 2`
Squaring both sides:
`(tan θ + 1/tan θ)^2 = 2^2`
`tan^2 θ + 1/(tan^2 θ) + 2(tan θ) (1/tan θ) = 4`
`tan^2 θ + 1/(tan^2θ) + 2 = 4`
`tan^2 θ + 1/(tan^2 θ) = 4 - 2`
`tan^2 θ + 1/(tan^2 θ) = 2`
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