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If show thatdydxsin-1(x5-y5x5+y5)=π6,show thatdydx=x43y4 - Mathematics and Statistics

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प्रश्न

If `sin^-1((x^5 - y^5)/(x^5 + y^5)) = pi/(6), "show that" "dy"/"dx" = x^4/(3y^4)`

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उत्तर

`sin^-1((x^5 - y^5)/(x^5 + y^5)) = pi/(6)`

∴ `(x^5 - y^5)/(x^5 + y^5) = sin  pi/(6) = (1)/(2)`
∴ 2x5 – 2y5 = x5 + y5
∴ 3y5 = x5
Differentiating both sides w.r.t. x, we get
`3 xx 5y^4"dy"/"dx"` = 5x4

∴ `"dy"/"dx" = x^4/(3y^4)`.

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अध्याय 1: Differentiation - Exercise 1.3 [पृष्ठ ४०]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.3 | Q 5.05 | पृष्ठ ४०

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