Question

If sec θ + tan θ + 1 = 0 then (sec θ – tan θ) = ?

विकल्प

• 1

• –1

• 0

• 2

Answer 1

–1

Explanation:

sec θ + tan θ + 1 = 0 

⇒ sec θ + tan θ = –1

(sec²θ – tan²θ) = 1 

⇒ (sec θ + tan θ)(sec θ – tan θ) = 1

⇒ (–1) × (sec θ – tan θ) = 1

⇒ (sec θ – tan θ) = –1