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प्रश्न
If the ratio of the sum of first n terms of two A.P’s is (7n +1): (4n + 27), find the ratio of their mth terms.
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उत्तर
Let a1, a2 be the first terms and d1, d2 the common differences of the two given A.P’s.
Then we have `S_n=n/2[2a_1+(n-1)d_1] " and " S_n=n/2[2a_2+(n-1)d_2]`
∴ `S_n/S_n=(n/2[2a_1+(n-1)d_1])/(n/2[2a_2+(n-1)d_2])=(2a_1+(n-1)d_1) /(2a_2+(n-1)d_2)`
It is given that `S_n/S_n=(7n+1)/(4n+27)`
`:.(2a_1+(n-1)d_1)/(2a_2+(n-1)d_2)=(7n+1)/(4n+27) "....(1)"`
To find the ratio of the mth terms of the two given A.P.'s replace n by (2m-1) in equation (1).
`:.(2a_1+(2m-1-1)d_1)/(2a_2+(2m-1-1)d_2)=(7(2m-1)+1)/(4(2m-1)+27)`
`:.(2a_1+(2m-1)d_1)/(2a_2+(2m-2)d_2)=(14m-7+1)/(8m-4+27)`
`:.(a_1+(m-1)d_1)/(a_2+(m-1)d_2)=(14m-6)/(8m+23)`
Hence, the ratio of the mth terms of the two A.P's is 14m-6 : 8m + 23
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