If P + Q = 8 and P - Q = 4, Find: P2 + Q2 - Mathematics

If p + q = 8 and p - q = 4, find:
p²+ q²

योग

Putting pq = 12 in (i) we get :
p² + q²
= 64 - 2(12)
= 64 - 24
= 40.

shaalaa.com

क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

अध्याय 4: Expansions - Exercise 4.1

अध्याय 4 Expansions
Exercise 4.1 | Q 12.2

Simplify the expression:

`(x + y + z)^2 + (x + y/2 + 2/3)^2 - (x/2 + y/3 + z/4)^2`

Find the following product:

\[\left( \frac{3}{x} - \frac{5}{y} \right) \left( \frac{9}{x^2} + \frac{25}{y^2} + \frac{15}{xy} \right)\]

If \[\frac{a}{b} + \frac{b}{a} = - 1\] then a³ − b³ =

Use the direct method to evaluate :
(2a+3) (2a−3)

Evaluate: (9 − y) (7 + y)

Evaluate: (5xy − 7) (7xy + 9)

Expand the following:

`(2"a" + 1/(2"a"))^2`

Simplify by using formula :
(a + b - c) (a - b + c)

Simplify:

`("a" - 1/"a")^2 + ("a" + 1/"a")^2`

Simplify:
(x + y - z)² + (x - y + z)²