Advertisements
Advertisements
प्रश्न
If p + q = 12 and pq = 22, then find p2 + q2.
Advertisements
उत्तर
Given, p + q = 12 and pq = 22
Since, (p + q)2 = p2 + q2 + 2pq ...[Using the identity, (a + b)2 = a2 + b2 + 2ab]
∴ (12)2 = p2 + q2 + 2 × 22
⇒ p2 + q2 = (12)2 – 44
⇒ p2 + q2 = 144 – 44 = 100
APPEARS IN
संबंधित प्रश्न
Find the following squares by suing the identities
(xy + 3z)2
Using (x + a) (x + b) = x2 + (a + b) x + ab, find 103 × 104
Use an expansion formula to find the value.
(1005)2
Expand:
(2a – 3b)2
Expand:
`("y" - 3/"y")^2`
Factors of 9x2 + 6xy are
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x2 + 2ax + 1
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x3 + 2abx2 + b2x
The area of a square is given by 4x2 + 12xy + 9y2. Find the side of the square.
Factorise `x^2 + 1/x^2 + 2 - 3x - 3/x`.
