Advertisements
Advertisements
प्रश्न
Factorise the following using suitable identity
a2 + 6ab + 9b2 – c2
Advertisements
उत्तर
a2 + 6ab + 9b2 – c2 = a2 + 2 × a × 3b + 32b2 – c2
= a2 + (2 × a × 3b) + (3b)2 – c2
This expression is of the form of identity
[a2 + 2ab + b2] – c2 = (a + b)2 – c2
a2 + (2 × a × 3b) + (3b)2 – c2 = (a + 3b)2 – c2
Again this R.H.S is of the form of identity
a2 – b2 = (a + b)(a – b)
(a + 3b)2 – c2 = [(a + 3b) + c][(a + 3b) – c]
a2 + 6ab + 9b2 – c2 = (a + 3b + c)(a + 3b – c)
APPEARS IN
संबंधित प्रश्न
Simplify (2.5p − 1.5q)2 − (1.5p − 2.5q)2
Using (x + a) (x + b) = x2 + (a + b) x + ab, find 103 × 104
Using (x + a) (x + b) = x2 + (a + b) x + ab, find 103 × 98
Expand (ax + by)2
Use an expansion formula to find the value.
(997)2
Use the formula to multiply the following.
(3x − 5) (3x + 5)
Expand (3m + 5)2
The sum of areas of two squares with sides 4a and 4b is ______.
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
4x2 + 12x + 9
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
16x2 + 40x + 25
