Advertisements
Advertisements
प्रश्न
Factorise the following using suitable identity
a2 + 6ab + 9b2 – c2
Advertisements
उत्तर
a2 + 6ab + 9b2 – c2 = a2 + 2 × a × 3b + 32b2 – c2
= a2 + (2 × a × 3b) + (3b)2 – c2
This expression is of the form of identity
[a2 + 2ab + b2] – c2 = (a + b)2 – c2
a2 + (2 × a × 3b) + (3b)2 – c2 = (a + 3b)2 – c2
Again this R.H.S is of the form of identity
a2 – b2 = (a + b)(a – b)
(a + 3b)2 – c2 = [(a + 3b) + c][(a + 3b) – c]
a2 + 6ab + 9b2 – c2 = (a + 3b + c)(a + 3b – c)
APPEARS IN
संबंधित प्रश्न
Find the following squares by suing the identities.
(b − 7)2
Find the following squares by suing the identities.
`(2/3 m + 3/4 n)^2`
Using a2 − b2 = (a + b) (a − b), find 1532 − 1472
Using a2 − b2 = (a + b) (a − b), find 12.12 − 7.92
Using (x + a) (x + b) = x2 + (a + b) x + ab, find 5.1 × 5.2
Use a formula to multiply of (4z – 5y)(4z + 5y)
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
x2 + 12x + 36
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x2 + 2ax + 1
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
`x^2/4 + 2x + 4`
The area of a square is 9x2 + 24xy + 16y2. Find the side of the square.
