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प्रश्न
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find P – Q + R
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उत्तर
P = − 12x2 – 10xy + 5y2
Q = 7x2 + 6xy + 2y2
R = 5x2 + 2xy + 4y2
P – Q + R = (– 12x2 – 10xy + 5y2) – (7x2 + 6xy + 2y2) + (5x2 + 2xy + 4y2)
= – 12x2 – 10xy + 5y2 – 7x2 – 6xy – 2y2 + 5x2 + 2xy + 4y2
= – 12x2 – 7x2 + 5x2 – 10xy – 6xy + 2xy + 5y2 – 2y2 + 4y2
= – 14x2 – 14xy + 7y2
संबंधित प्रश्न
Find the value of 3a − 2b, when a = 8 and b = 10
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yx
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a − (a − b − c)
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− m − n − (− m) − m
Simplify:
x − (y − z) + x + (y − z) + y − (z + x)
Simplify:
x − [y + {x − (y + x)}]
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find Q + P
Multiply and then evaluate:
(x2 – y) and (xy – y2); when x = 1 and y = 2.
