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प्रश्न
If matrix A = `[(-p, q),(r, p)]` is such that A2 = I, then ______.
विकल्प
1 + p2 + qr = 0
1 − p2 − qr = 0
1 − p2 + qr = 0
1 + p² − qr = 0
MCQ
रिक्त स्थान भरें
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उत्तर
If matrix A = `[(-p, q),(r, p)]` is such that A2 = I, then 1 − p2 − qr = 0.
Explanation:
A2 = A × A
= `[(-p, q),(r, p)] [(-p, q),(r, p)]`
= `[((-p)(-p) + (q)(r), (-p)(q) + (q)(p)),((r)(-p) + (p)(r), (r)(q) + (p)(p))]`
= `[(p^2 + qr, -pa + pq),(-rp + pr, qr + p^2)]`
= `[(p^2 + qr, 0),(0, p^2 + qr)]`
Equate A2 to the Identity Matrix (I):
A2 = I
I = `[(1, 0),(0, 1)]`
`[(p^2 + qr, 0),(0, p^2 + qr)] = [(1, 0),(0, 1)]`
Compare the elements:
p2 + qr = 1
1 − p2 − qr = 0
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