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प्रश्न
If m2 = -2 and n = 2; find the values of: 2n3 – 3m
योग
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उत्तर
2n3 – 3m
m = -2, n = 2
= 2(2)3 - 3(-2)
= 2 × (2 × 2 × 2) - 3 × (- 2)
= 16 - 3 × (-2)
= 16 + 6 = 22
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Laws of Exponents (Through Observing Patterns to Arrive at Generalisation.)
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