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If Log Y = Tan−1 X, Show that (1 + X2)Y2 + (2x − 1) Y1 = 0 ? - Mathematics

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प्रश्न

If log y = tan−1 x, show that (1 + x2)y2 + (2x − 1) y1 = 0 ?

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उत्तर

Here,

\[\log y = \tan^{- 1} x\]

\[\text { Differentiating w . r . t . x, we get }\]

\[\frac{1}{y} \times y_1 = \frac{1}{1 + x^2}\]

\[ \Rightarrow \left( 1 + x^2 \right) y_1 = y\]

\[ \Rightarrow \left( 1 + x^2 \right) y_2 + 2x y_1 = y_1 \]

\[ \Rightarrow \left( 1 + x^2 \right) y_2 + 2x y_1 - y_1 = 0\]

\[ \Rightarrow \left( 1 + x^2 \right) y_2 + \left( 2x - 1 \right) y_1 = 0\]

Hence proved.

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अध्याय 12: Higher Order Derivatives - Exercise 12.1 [पृष्ठ १७]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 12 Higher Order Derivatives
Exercise 12.1 | Q 25 | पृष्ठ १७

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