Advertisements
Advertisements
प्रश्न
If in two triangles ABC and PQR, `(AB)/(QR) = (BC)/(PR) = (CA)/(PQ)`, then ΔPQR ∼ ______.
रिक्त स्थान भरें
Advertisements
उत्तर
If in two triangles ABC and PQR, `(AB)/(QR) = (BC)/(PR) = (CA)/(PQ)`, then ΔPQR ∼ ΔCAB.
Explanation:
Since `(AB)/(QR) = (BC)/(PR) = (CA)/(PQ)`, the three pairs of corresponding sides are proportional, so by SSS similarity ΔABC ∼ ΔQRP (A↔Q, B↔R, C↔P). Relabeling vertices gives ΔPQR ∼ ΔCAB.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
