Advertisements
Advertisements
प्रश्न
If each term of a G.P. is raised to the power x, show that the resulting sequence is also a G.P.
Advertisements
उत्तर
Let a1, a2, a3, ................., an, .......... be a G.P. with common ratio r.
`=> (a_(n + 1))/a_n = r` for all n ∈ N
If each term of a G.P. is raised to the power x, we get the sequence `a_1^x, a_2^x, a_3^x, ............, a_n^x,.........`
Now, `(a_(n + 1))^x/(a_n)^x = ((a_(n + 1))/a_n)^x = r^x` for all n ∈ N
Hence, `a_1^x, a_2^x, a_3^x, ............, a_n^x,.........` is also a G.P.
संबंधित प्रश्न
Find the G.P. whose first term is 64 and next term is 32.
The product of 3rd and 8th terms of a G.P. is 243. If its 4th term is 3, find its 7th term.
For the G.P. `1/27, 1/9, 1/3, ........., 81`; find the product of fourth term from the beginning and the fourth term from the end.
Q 6
If a, b, c are in G.P. and a, x, b, y, c are in A.P., prove that `1/x + 1/y = 2/b`
Q 6
Find the sum of G.P. :
0.3 + 0.03 + 0.003 + 0.0003 + ........... to 8 items.
Find the sum of G.P. :
`1 - 1/2 + 1/4 - 1/8 + ..........` to 9 terms.
Find the sum of G.P. :
`1 - 1/3 + 1/3^2 - 1/3^3 + .........` to n terms.
Find the geometric mean between 14 and `7/32`
