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प्रश्न
For the G.P. `1/27, 1/9, 1/3, ........., 81`; find the product of fourth term from the beginning and the fourth term from the end.
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उत्तर
Given G.P. : `1/27, 1/9, 1/3, ........., 81`
Here,
Common ratio, r = `(1/9)/(1/27)` = 3
First term, a = `1/27` and last term, l = 81
∴ 4th term from the beginning = ar3
= `1/27 xx (3)^3`
= `1/27 xx 27`
= 1
And 4th term from an end = `1/r^3`
= `81/(3)^3`
= `81/27`
= 3
Thus, required product = 1 × 3 = 3
संबंधित प्रश्न
Find the seventh term from the end of the series :
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Q 5
If a, b and c are in A.P, a, x, b are in G.P. whereas b, y and c are also in G.P.
Show that : x2, b2, y2 are in A.P.
If a, b and c are in A.P. and also in G.P., show that : a = b = c.
Find the sum of G.P. :
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Find the sum of G.P. : 3, 6, 12, .........., 1536.
Find the geometric mean between `4/9` and `9/4`
Find the geometric mean between 2a and 8a3
Q 2
The first term of a G.P. is –3 and the square of the second term is equal to its 4th term. Find its 7th term.
