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प्रश्न
If the diagram in Fig. 2.22 shows the graph of the polynomial f(x) = ax2 + bx + c, then

विकल्प
a > 0, b < 0 and c > 0
a < 0, b < 0 and c < 0
a < 0, b > 0 and c > 0
a < 0, b > 0 and c < 0
MCQ
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उत्तर
Clearly, `f(x) = ax^2 +bx +c` represent a parabola opening upwards.

Therefore, ` a > 0` cuts Y axis at P which lies on `OY`. Putting x = 0 in `y = ax^2 + bx + c`, we get y = c. So the coordinates of P is `(0,c)`. Clearly, P lies on `OY`. Therefore `c < 0`
Hence, the correct choice is `(a)`
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