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If a = [ Cos X Sin X − Sin X Cos X ] , Find X Satisfying 0 < X < π 2 When a + at = I

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प्रश्न

If \[A = \begin{bmatrix}\cos x & \sin x \\ - \sin x & \cos x\end{bmatrix}\] , find x satisfying 0 < x < \[\frac{\pi}{2}\] when A + AT = I

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उत्तर

\[Given: A = \begin{bmatrix}\cos x & \sin x \\ - \sin x & \cos x\end{bmatrix}\] 

\[ A^T = \begin{bmatrix}\cos x & - \sin x \\ \sin x & \cos x\end{bmatrix}\] 

\[Now, \] 

\[A + A^T = I\] 

\[ \Rightarrow \begin{bmatrix}\cos x & \sin x \\ - \sin x & \cos x\end{bmatrix} + \begin{bmatrix}\cos x & - \sin x \\ \sin x & \cos x\end{bmatrix} = \begin{bmatrix}1 & 0 \\ 0 & 1\end{bmatrix}\] 

\[ \Rightarrow \begin{bmatrix}\cos x + \cos x & \sin x - \sin x \\ - \sin x + \sin x & \cos x + \cos x\end{bmatrix} = \begin{bmatrix}1 & 0 \\ 0 & 1\end{bmatrix}\] 

\[ \Rightarrow \begin{bmatrix}2\cos x & 0 \\ 0 & 2\cos x\end{bmatrix} = \begin{bmatrix}1 & 0 \\ 0 & 1\end{bmatrix}\] 

\[ \Rightarrow 2\cos x = 1 \] 

\[ \Rightarrow \cos x = \frac{1}{2}\] 

\[ \Rightarrow x = \frac{\pi}{3}\] 

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अध्याय 4: Algebra of Matrices - Exercise 5.6 [पृष्ठ ६२]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 4 Algebra of Matrices
Exercise 5.6 | Q 8 | पृष्ठ ६२
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