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If ∣ ∣ ∣ ∣ a B − Y C − Z a − X B C − Z a − X B − Y C ∣ ∣ ∣ ∣ = 0, Then Using Properties of Determinants, Find the Value of a X + B Y + C Z , Where X , Y , Z ≠

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प्रश्न

If \[\begin{vmatrix}a & b - y & c - z \\ a - x & b & c - z \\ a - x & b - y & c\end{vmatrix} =\] 0, then using properties of determinants, find the value of  \[\frac{a}{x} + \frac{b}{y} + \frac{c}{z}\]  , where \[x, y, z \neq\] 0

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उत्तर

\[\begin{vmatrix}a & b - y & c - z \\ a - x & b & c - z \\ a - x & b - y & c\end{vmatrix} =\] 0
\[R_1 \to R_1 - R_2 \] 
\[\begin{vmatrix}x & - y & 0 \\ a - x & b & c - z \\ a - x & b - y & c\end{vmatrix} = 0\] 
\[ R_2 \to R_2 - R_3 \] 
\[ \Rightarrow \begin{vmatrix}x & - y & 0 \\ 0 & y & - z \\ a - x & b - y & c\end{vmatrix} = 0\] 
\[\text{ Expanding along first row, we get }\] 
\[x(yc + zb - zy) + y(0 - za + zx) = 0\] 
\[ \Rightarrow xyc + xzb - xyz + zya - xyz = 0 \] 
\[xyc + xzb - 2xyz + zya = 0\] 
\[\text{ Dividing by xyz, we get }\] 
\[\frac{c}{z} + \frac{b}{y} - 2 + \frac{a}{x} = 0\] 
\[ \therefore \frac{a}{x} + \frac{b}{y} + \frac{c}{z} = 2\]
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अध्याय 5: Determinants - Exercise 6.2 [पृष्ठ ६२]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 5 Determinants
Exercise 6.2 | Q 54 | पृष्ठ ६२

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