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If → a and → B Are Perpendicular Vectors, ∣ ∣ → a + → B ∣ ∣ = 3 and | → a | = 5 Find the Value of ∣ ∣ → B ∣ ∣

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प्रश्न

If \[\vec{a}\] and \[\vec{b}\] are perpendicular vectors, \[\left| \vec{a} + \vec{b} \right| = 13\] and \[\left| \vec{a} \right| = 5\] find the value of \[\left| \vec{b} \right|\]

योग
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उत्तर

\[\left| \vec{a} + \vec{b} \right| = 13\]  has been taken in order to solve the question. It is given that  \[\vec{a}\] and \[\vec{b}\] are perpendicular vectors.

\[\therefore \vec{a} . \vec{b} = 0\] 

\[\left| \vec{a} + \vec{b} \right| = 13\]
\[ \Rightarrow \left| \vec{a} + \vec{b} \right|^2 = 169\]
\[ \Rightarrow \left| \vec{a} \right|^2 + 2 \vec{a} . \vec{b} + \left| \vec{b} \right|^2 = 169\]
\[ \Rightarrow 25 + 2 \times 0 + \left| \vec{b} \right|^2 = 169............. \left[ \text{ Using }\left( 1 \right) \right]\]  

\[\Rightarrow \left| \vec{b} \right|^2 = 169 - 25 = 144\]
\[ \Rightarrow \left| \vec{b} \right| = 12\]  

Thus, the value of \[\left| \vec{b} \right|\] is 12 

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अध्याय 23: Scalar Or Dot Product - very short answer [पृष्ठ ४८]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 23 Scalar Or Dot Product
very short answer | Q 39 | पृष्ठ ४८
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