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If ЁЭЫ╝, ЁЭЫ╜ Are the Zeroes of the Polynomial `F(X) = 5x^2 -7x + 1` Then `1/тИЭ+1/╬▓=?` - Mathematics

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If ЁЭЫ╝, ЁЭЫ╜ are the zeroes of the polynomial `f(x) = 5x^2 -7x + 1` then `1/∝+1/β=?` 

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By using the relationship between the zeroes of he quadratic polynomial. We have 

Sum of zeroes=`(-("Coefficient of x"))/("Coefficient of "x^2)`Sum of zeroes = `"Constant term"/("Coefficient of" x^2) ` 

∴` ∝+β=-(-7)/5 and ∝β=1/5` 

⇒` ∝+β =7/5 and ∝β=1/5` 

Now,`1/∝+1/β= (∝+β)/(∝β)` 

=`(7/5)/(1/5)` 

= 7

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рдЕрдзреНрдпрд╛рдп 2: Polynomials - Exercises 3

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