Advertisements
Advertisements
प्रश्न
If ΔABC is a right triangle such that ∠C = 90°, ∠A = 45° and BC =7units, find ∠B, AB and AC.
Advertisements
उत्तर
∠C = 90°, ∠A = 45°
∠A + ∠B + ∠C = 180°
45° + ∠B + 90° = 180°
∠B = 180° - 135°
∠= 45°
sin45° = `"BC"/"AB"`
⇒ AB = `"BC"/"sin45°"`
⇒ AB = `(7)/(1/sqrt(2)`
⇒ AB = `7sqrt(2)"units"`
Also,
tan45° = `"BC"/"AC"`
⇒ AC = `"BC"/tan45°"`
⇒ AC = `(7)/(1)`
⇒ AC = 7units.
APPEARS IN
संबंधित प्रश्न
Find the value of 'A', if `sqrt(3)cot"A"` = 1
Solve for 'θ': cot2(θ - 5)° = 3
Solve for 'θ': `sec(θ/2 + 10°) = (2)/sqrt(3)`
If tanθ= cotθ and 0°≤ θ ≤ 90°, find the value of 'θ'.
If θ = 30°, verify that: 1 - sin 2θ = (sinθ - cosθ)2
In the given figure, PQ = 6 cm, RQ = x cm and RP = 10 cm, find
a. cosθ
b. sin2θ- cos2θ
c. Use tanθ to find the value of RQ
In the given figure, AB and EC are parallel to each other. Sides AD and BC are 1.5 cm each and are perpendicular to AB. Given that ∠AED = 45° and ∠ACD = 30°. Find:
a. AB
b. AC
c. AE
Find the value 'x', if:
The perimeter of a rhombus is 100 cm and obtuse angle of it is 120°. Find the lengths of its diagonals.
Evaluate the following: cot27° - tan63°
