Question

If a pair of dice is thrown once, then what is the probability of getting a sum of 8?

Answer 1

Number of possible outcomes, n(S) = 36

The favourable outcomes are (sum of getting 8)

= {(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)}

i.e., n(E) = 5

∴ Probability (getting sum of 8)

= `(n(E))/(n(S))`

= `5/36`