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प्रश्न
If A × A has 16 elements, S = {(a, b) ∈ A × A : a < b} ; (−1, 2) and (0, 1) are two elements of S, then find the remaining elements of S
योग
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उत्तर
Given A × A has 16 elements.
∴ A has 4 elements.
Also S = {(a, b) ∈ A × A: a < b}
Given (−1, 2) and (0, 1) ∈ S
A = {−1, 0, 1, 2}
The elements of S are
S = {(−1, 0), (−1, 1), (−1, 2), (0, 1), (0, 2), (1, 2)}
∴ The other elements of the sets are
((− 1, 0), (− 1, 1), (0, 2), (1, 2)}
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