हिंदी

If A = 60° and B = 30°, verify that sin (A + B) = sin A cos B + cos A sin B.

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प्रश्न

If A = 60° and B = 30°, verify that sin (A + B) = sin A cos B + cos A sin B.

योग
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उत्तर

A = 600 and B = 30
Now, A + B = 600 + 300 = 90
Also, A – B = 600 – 300 = 300  
sin (A + B) = sin 900 = 1 
sin A cos B + cos A sin B = sin 600 cos 300 + cos 600 sin 30

=`(sqrt(3)/2xx sqrt(3)/2 + 1/2xx1/2) = (3/4+1/4)=1`

∴ sin (A + B) = sin A cos B + cos A sin B

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अध्याय 11: T-Ratios of Some Particular Angles - EXERCISE 11 [पृष्ठ ५७२]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 11 T-Ratios of Some Particular Angles
EXERCISE 11 | Q 14. (i) | पृष्ठ ५७२
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