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प्रश्न
If `"a" - 1/"a" = 10`; find `"a"^2 - 1/"a"^2`
योग
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उत्तर
`"a"^2 - 1/"a"^2`
= `("a" + 1/"a") ("a" - 1/"a")`
= `(±2sqrt(26)) (10)`
= ±20`sqrt(26)`.
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