Advertisements
Advertisements
प्रश्न
If `"a" - 1/"a" = 10`; find `"a"^2 - 1/"a"^2`
योग
Advertisements
उत्तर
`"a"^2 - 1/"a"^2`
= `("a" + 1/"a") ("a" - 1/"a")`
= `(±2sqrt(26)) (10)`
= ±20`sqrt(26)`.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Verify that `x^3+y^3+z^3-3xyz=1/2(x+y+z)[(x-y)^2+(y-z)^2+(z-x)^2]`
Simplify the following:
0.76 x 0.76 - 2 x 0.76 x 0.24 x 0.24 + 0.24
Write in the expanded form: `(x + 2y + 4z)^2`
Simplify of the following:
(x+3)3 + (x−3)3
Find the following product:
\[\left( 3 + \frac{5}{x} \right) \left( 9 - \frac{15}{x} + \frac{25}{x^2} \right)\]
If x = −2 and y = 1, by using an identity find the value of the following
\[\left( 5y + \frac{15}{y} \right) \left( 25 y^2 - 75 + \frac{225}{y^2} \right)\]
Use identities to evaluate : (97)2
Use the direct method to evaluate :
`("z"-2/3)("z"+2/3)`
Simplify:
(3x + 5y + 2z)(3x - 5y + 2z)
Using suitable identity, evaluate the following:
101 × 102
