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If 3 Sin ( X Y ) + 4 Cos ( X Y ) = 5 , Then D Y D X = - Mathematics

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प्रश्न

If \[3 \sin \left( xy \right) + 4 \cos \left( xy \right) = 5, \text { then } \frac{dy}{dx} =\] _____________ .

विकल्प

  • \[- \frac{y}{x}\]

  • \[\frac{3 \sin \left( xy \right) + 4 \cos \left( xy \right)}{3 \cos \left( xy \right) - 4 \sin \left( xy \right)}\]

  • \[\frac{3 \cos \left( xy \right) + 4 \sin \left( xy \right)}{4 \cos \left( xy \right) - 3 \sin \left( xy \right)}\]

  • none of these

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उत्तर

\[- \frac{y}{x}\]

 

\[\text { We have, } 3 \sin\left( xy \right) + 4 \cos\left( xy \right) = 5 \]
\[ \Rightarrow 3 \cos\left( xy \right)\left[ x\frac{dy}{dx} + y \right] - 4 \sin\left( xy \right)\left[ x\frac{dy}{dx} + y \right] = 0\]
\[ \Rightarrow \left[ x\frac{dy}{dx} + y \right]\left[ 3 \cos\left( xy \right) - 4 \sin\left( xy \right) \right] = 0\]
\[ \Rightarrow x\frac{dy}{dx} + y = 0\]
\[ \Rightarrow x\frac{dy}{dx} = - y\]
\[ \therefore \frac{dy}{dx} = - \frac{y}{x}\]

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अध्याय 11: Differentiation - Exercise 11.10 [पृष्ठ १२०]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 11 Differentiation
Exercise 11.10 | Q 18 | पृष्ठ १२०

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