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प्रश्न
If `2/x + 3/y = 6` and `1/x + 1/(2y) = 2` then
विकल्प
`x = 1, y = 2/3`
`x = 2/3, y = 1`
`x = 1, y = 3/2`
`x = 3/2, y = 1`
MCQ
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उत्तर
`bb(x = 2/3, y = 1)`
Explanation:
Put `a = 1/x` and `b = 1/y`.
Then 2a + 3b = 6 and `a + (1/2)b = 2`.
Multiply the second equation by 2:
2a + b = 4
Subtract from the first:
2b = 2
⇒ b = 1
⇒ y = 1
Substitute back:
2a + 1 = 4
⇒ `a = 3/2`
⇒ `x = 2/3`
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