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प्रश्न
If 2 sin θ + 3 cos θ = 2, then 3 sin θ – 2 cos θ = ______.
रिक्त स्थान भरें
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उत्तर
If 2 sin θ + 3 cos θ = 2, then 3 sin θ – 2 cos θ = ±3.
Explanation:
Square and add the two expressions:
(2 sin θ + 3 cos θ)2 + (3 sin θ – 2 cos θ)2 = (4 + 9)
(sin2 θ + cos2 θ) = 13
Given 2 sin θ + 3 cos θ = 2.
Substitute to get 4 + (3 sin θ – 2 cos θ)2 = 13.
So (3 sin θ – 2 cos θ)2 = 9 and hence 3 sin θ – 2 cos θ = ±3.
This sign depends on the particular θ.
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