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प्रश्न
Identify in the following reaction (a) the substance oxidised, and (b) the substance reduced:
\[\ce{ZnO + C -> Zn + CO}\]
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उत्तर
- The substance oxidised in the reaction is Carbon (C). Carbon gains oxygen to transform into carbon monoxide. The oxidation state of carbon increases from 0 to +2 in CO.
- The substance reduced is Zinc oxide (ZnO). Zinc oxide loses oxygen to form metallic zinc (Zn). The oxidation state of zinc decreases from +2 in ZnO to 0 in Zn.
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संबंधित प्रश्न
Identify the substances that are oxidised and the substances that are reduced in the following reaction.
\[\ce{4Na(s) + O2(g) -> 2Na2O(s)}\]
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(b) name the substance reduced
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(d) name the reducing agent
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H2 + S → ___________
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| OPTION | Substance Oxidized | Reducing Agent |
| A | Fe | Fe |
| B | Fe | FeSO4 |
| C | Cu | Fe |
| D | CuSO4 | Fe |
Choose the odd one out and write the reason:
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\[\ce{CH3 - CH2 - OH ->[{[O]}][K2Cr2O7/H2SO4] CH3 - COOH}\]
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- What is the role of the chemical written on the arrow?
- Give one example of one such type of chemical as in answer (b).
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\[\ce{MnO_2 + 4HCl->MnCl_2 +2H_2O + Cl_2}\]
The oxidizing agent in the equation \[\ce{S + 2H2SO4 -> 3SO2 + 2H2O}\] is ______.
