Question

(i) x² – y² + 2xy = (x + y)²

(ii) `x^2 - (a + 1/a)x + 1 = (x - a)(x + 1/a)`

विकल्प

• Only (i)

• Only (ii)

• Both (i) and (ii)

• Neither (i) nor (ii)

Answer 1

Neither (i) nor (ii)

Explanation:

Let’s analyze the two statements given:

(i) x² – y² + 2xy = (x + y)²

Expanding the right side: (x + y)² = x² + 2xy + y²

But the left side is x² – y² + 2xy

Since x² – y² + 2xy ≠ x² + 2xy + y² is false.

(ii) `x^2 - (a + 1/a)x + 1 = (x - a)(x + 1/a)`

Expanding the right side:

`(x - a)(x + 1/a) = x^2 + x/a - ax - 1`

`(x - a)(x + 1/a) = x^2 - (a - 1/a)x - 1`

But the left side is `x^2 - (a + 1/a)x + 1`

Since the signs and constants do not match is false.