Advertisements
Advertisements
प्रश्न
How is peak current related to peak EMF and external resistance?
विकल्प
\[I_0=\varepsilon_0+R\]
\[I_0=\frac{\varepsilon_0}{R}\]
\[I_0=\varepsilon_0R\]
\[I_0=\frac{R}{\varepsilon_0}\]
MCQ
Advertisements
उत्तर
Peak current is the current amplitude through resistance \[R\]. It equals peak EMF divided by resistance: \[I_0=\frac{\varepsilon_0}{R}\].
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
