Advertisements
Advertisements
प्रश्न
Heavy stable nucle have more neutrons than protons. This is because of the fact that ______.
विकल्प
neutrons are heavier than protons.
electrostatic force between protons are repulsive.
neutrons decay into protons through beta decay.
nuclear forces between neutrons are weaker than that between protons.
Advertisements
उत्तर
Heavy stable nucle have more neutrons than protons. This is because of the fact that electrostatic force between protons are repulsive.
Explanation:
Neutron-proton ratio `(N/2 "ratio")`: The chemical properties of an atom are governed entirely by the number of protons (Z) in the nucleus, the Stability of an. atom appears to depend on both the number of protons and the number of neutrons.
- For lighter nuclei, the greatest stability is achieved when the number of protons and neutrons are approximately equal (N = Z), ie. `N/Z` = 1
- Heavy nuclei are stable only when they have more neutrons than protons. Thus heavy nuclei are neutron-rich compared to lighter nuclei (for heavy nuclei, more the protons in the nucleus, the greater the electrical repulsive force between them. Therefore more neutrons are added to provide the strong attractive forces necessary to keep the nucleus stable.)
APPEARS IN
संबंधित प्रश्न
Write symbolically the nuclear β+ decay process of `""_6^11C` Is the decayed product X an isotope or isobar of (`""_6^11C`)? Given the mass values m (`""_6^11C`) = 11.011434 u and m (X) = 11.009305 u. Estimate the Q-value in this process.
Obtain the binding energy (in MeV) of a nitrogen nucleus `(""_7^14"N")`, given `"m"(""_7^14"N")` = 14.00307 u.
The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energies of the nuclei `""_20^41"Ca"` and `""_13^27 "Al"` from the following data:
`"m"(""_20^40"Ca")` = 39.962591 u
`"m"(""_20^41"Ca")` = 40.962278 u
`"m"(""_13^26"Al")` = 25.986895 u
`"m"(""_13^27"Al")` = 26.981541 u
What is the significance of binding energy per nucleon of a nucleus of a radioactive element?
Use this graph to explain the release of energy in both the processes of nuclear fusion and fission.
Is it easier to take out a nucleon (a) from carbon or from iron (b) from iron or from lead?
If the nucleons of a nucleus are separated from each other, the total mass is increased. Where does this mass come from?
Find the binding energy per nucleon of `""_79^197"Au"` if its atomic mass is 196.96 u.
(Use Mass of proton mp = 1.007276 u, Mass of `""_1^1"H"` atom = 1.007825 u, Mass of neutron mn = 1.008665 u, Mass of electron = 0.0005486 u ≈ 511 keV/c2,1 u = 931 MeV/c2.)
Calculate mass defect and binding energy per nucleon of `"_10^20 Ne`, given
Mass of `"_10^20 Ne= 19.992397` u
Mass of `"_0^1H = 1.007825` u
Mass of `"_0^1n = 1.008665` u
Sketch a graph showing the variation of binding energy per nucleon of a nucleus with its mass number.
The figure shows the plot of binding energy (BE) per nucleon as a function of mass number A. The letters A, B, C, D, and E represent the positions of typical nuclei on the curve. Point out, giving reasons, the two processes (in terms of A, B, C, D, and E ), one of which can occur due to nuclear fission and the other due to nuclear fusion.
Answer the following question.
Draw the curve showing the variation of binding energy per nucleon with the mass number of nuclei. Using it explains the fusion of nuclei lying on the ascending part and fission of nuclei lying on the descending part of this curve.
An electron in hydrogen atom stays in its second orbit for 10−8 s. How many revolutions will it make around the nucleus at that time?
Tritium is an isotope of hydrogen whose nucleus Triton contains 2 neutrons and 1 proton. Free neutrons decay into `p + bare + barν`. If one of the neutrons in Triton decays, it would transform into He3 nucleus. This does not happen. This is because ______.
He23 and He13 nuclei have the same mass number. Do they have the same binding energy?
Nuclei with magic no. of proton Z = 2, 8, 20, 28, 50, 52 and magic no. of neutrons N = 2, 8, 20, 28, 50, 82 and 126 are found to be very stable.
(i) Verify this by calculating the proton separation energy Sp for 120Sn (Z = 50) and 121Sb = (Z = 51).
The proton separation energy for a nuclide is the minimum energy required to separate the least tightly bound proton from a nucleus of that nuclide. It is given by `S_P = (M_(z-1^' N) + M_H - M_(ZN))c^2`.
Given 119In = 118.9058u, 120Sn = 119.902199u, 121Sb = 120.903824u, 1H = 1.0078252u.
(ii) What does the existance of magic number indicate?
What is meant by “binding energy per nucleon” of a nucleus?
Mp denotes the mass of a proton and Mn that of a neutron. A given nucleus, of binding energy B, contains Z protons and N neutrons. The mass M(N, Z) of the nucleus is given by (c is the velocity of light):
