Question

Half the perimeter of a garden, whose length is 4 more than its width is 36m. Find the dimensions of the garden

Answer 1

Let the length of the garden be x and width of the garden be y.

Then the equation formed are

x = y + 4 ….(1)

Half perimeter = 36

x + y = 36 ….(2)

y = x – 4

x	0	4
y	-4	0
Points	A	B

y = 36 – x

x	10	20
y	26	16
Points	C	D

Plotting these points we draw the lines AB and CD passing through them to represent the equations

The two lines AB and CD intersect at the point (20, 16), So, x = 20 and y = 16 is the required solution of the pair of linear equations i.e. length of the garden is 20 m and width of the garden is 16 m.

Verification:
Putting x = 20 and y = 16 in (1). We get

20 = 16 + 4 = 20, (1) is verified.

Putting x = 20 and y = 16 in (2). we get

20 + 16 = 36

36 = 36, (2) is verified.

Hence, both the equations are satisfied