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प्रश्न
Given \[y=a\sin(x+b)\], what is \[\frac{d^{2}y}{dx^{2}}\]?
विकल्प
\[\frac{d^{2}y}{dx^{2}}=-a\sin(x+b)\]
\[\frac{d^{2}y}{dx^{2}}=a\sin(x+b)\]
\[\frac{d^{2}y}{dx^{2}}=-a\cos(x+b)\]
\[\frac{d^{2}y}{dx^{2}}=a\cos(x+b)\]
MCQ
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उत्तर
Differentiate \[a\cos(x+b)\] with respect to \[x\]. Since the derivative of cosine is negative sine, the result is \[-a\sin(x+b)\].
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