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Given x - 3/x = 5, "find the value of"  x^3 - 27/x^3. - Mathematics

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प्रश्न

Given `x - 3/x = 5, "find the value of"  x^3 - 27/x^3.`

योग
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उत्तर

Here, `x - 3/x = 5,`

Using the identity,

`(x - a/x)^3 = x^3 - a^3/x^3 - 3a(x-a/x)`

Here, a = 3, so a3 = 27

`(x - 3/x)^3 = x^3 - 27/x^3 - 3(3) (x - 3/x)`

`(5)^3 = x^3 - 27/x^3 - 3(3) (5)`

`125 = x^3 - 27/x^3 - 45`

`125 + 45 = x^3 - 27/x^3`

∴ `x^3 - 27/x^3 = 170`

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अध्याय 3: Expansions - MISCELLANEOUS EXERCISE [पृष्ठ ३९]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
अध्याय 3 Expansions
MISCELLANEOUS EXERCISE | Q 3. (ii) | पृष्ठ ३९
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