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प्रश्न
Given log10 a = m, log10 b = n, log10 c = p, express k in terms of a, b and c if k = 102m + 3n – 5p.
योग
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उत्तर
Given, log10 a = m ⇒ a = 10m
log10 b = n ⇒ b = 10n
log10 c = p ⇒ c = 10p
Substitute these values in the expression for k:
k = 102m + 3n – 5p
Separate the powers:
k = 102m × 103n × 10−5p
Now substitute:
102m = a2
103n = b3
10−5p = `1/c^5`
So k = `a^2 xx b^3 xx 1/c^5`
k = `(a^2b^3)/c^5`
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