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Give the physical significance of self-inductance of a coil. - Physics

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प्रश्न

Give the physical significance of self-inductance of a coil.

दीर्घउत्तर
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उत्तर

When a circuit is switched on, the increasing current induces an emf which opposes the growth of current in a circuit. Likewise, when circuit is broken, the decreasing current induces an emf in the reverse direction. This emf now opposes the decay of current.

(a) Increasing current

(b) Decreasing current

Induced emf ε opposes the changing current i

Thus, the inductance of the coil opposes any change in current and tries to maintain the original state.

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Self – Induction
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Electromagnetic Induction And Alternating Current - Evaluation [पृष्ठ २६०]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 4 Electromagnetic Induction And Alternating Current
Evaluation | Q III. 8. | पृष्ठ २६०

संबंधित प्रश्न

A circular coil with a cross-sectional area of 4 cm2 has 10 turns. It is placed at the centre of a long solenoid that has 15 turns/cm and a cross-sectional area of 10 cm2. The axis of the coil coincides with the axis of the solenoid. What is their mutual inductance?


What is meant by mutual induction?


Define self-inductance of a coil interms of

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Assuming that the length of the solenoid is large when compared to its diameter, find the equation for its inductance.


An inductor of inductance L carries an electric current i. How much energy is stored while establishing the current in it?


Show that the mutual inductance between a pair of coils is same (M12 = M21).


Two air core solenoids have the same length of 80 cm and same cross–sectional area 5 cm2. Find the mutual inductance between them if the number of turns in the first coil is 1200 turns and that in the second coil is 400 turns.


A long solenoid having 400 turns per cm carries a current 2A. A 100 turn coil of cross-sectional area 4 cm2 is placed co-axially inside the solenoid so that the coil is in the field produced by the solenoid. Find the emf induced in the coil if the current through the solenoid reverses its direction in 0.04 sec.


The solenoids S1 and S2 are wound on an iron-core of relative permeability 900. The area of their cross-section and their length are the same and are 4 cm2 and 0.04 m, respectively. If the number of turns in S1 is 200 and that in S2 is 800, calculate the mutual inductance between the coils. The current in solenoid 1 is increased from 2A to 8A in 0.04 second. Calculate the induced emf in solenoid 2.


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